Answer:
we have:
(xy²)³ = x³.(y²)³ = x³y⁶ (1)
(xy³)² = x².(y³)² = x²y⁶ (2)
from (1)(2) => (xy²)³ isnt the same as (xy³)²
no it is not the first one is x cube y the power of 6 and the second one is x square y the power of 6
