Answer:
Q = 4133.2 J
Explanation:
Hello there!
In this case, since these calorimetry problems are based off the following heat equation involving heat (Q), mass (m), specific heat (C) and temperatures (T):
[tex]Q=mC(T_2-T_1)[/tex]
Thus, we plug in the given variables to obtain:
[tex]Q=62.0 g*2.433 \frac{J}{g\°C}* (40.5\°C-13.1\°C)\\\\Q=4133.2J[/tex]
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