Answer:
Solution given:
for second
we have
f(x)=x²-9x-36
let
y=x²-9x-36
when
x=0
y=-36
y=0
0=x²-9x-36
x²-12x+3x-36=0
x(x-12)+3(x-12)=0
(x-12)(x+3)=0
either
x=12
x=-3
So,
x and y intercepts are (-3,0)(12,0) and 0,-36)
