Step-by-step explanation:
[tex]\huge\mathcal\pink{here's \: your \: solution} \\ \\ \cos = base \div hypotenuse \: \\ \\ cos = j \div 8 \sqrt{2} \\ \\ \cos(45) = 1 \div \sqrt{2} \\ \\ j \div 8 \sqrt{2} = 1 \div \sqrt{2} \\ \\ j = 8 \sqrt{2} \div \sqrt{2} \\ \\ j = 8 inches \\ \\ \huge\mathfrak\purple{hope \: it \: helps..}[/tex]
