Answer:
V = 38.48 L
Explanation:
Given that,
No. of moles = 1.5 mol
Pressure, P = 700 torr
Temperature, T = 15°C = 288 K
We need to find the volume of the gas. The ideal gas equation is given by :
[tex]PV=nRT\\\\V=\dfrac{nRT}{P}\\\\V=\dfrac{1.5\times 62.36\times 288}{700}\\\\V=38.48\ L[/tex], R = L.Torr.K⁻¹.mol⁻¹
So, the required volume is equal to 38.48 L.
