Answer:
[tex]x^2+4x-7=(x+4)^2-23[/tex] where [tex]a=4[/tex] and [tex]b=-23[/tex]
Step-by-step explanation:
Given: [tex]x^2+4x-7[/tex]
Complete the square: [tex](x^2+4x+16)-23[/tex]
Reduce trinomial: [tex](x+4)^2-23[/tex]
Therefore, [tex]x^2+4x-7=(x+4)^2-23[/tex] where [tex]a=4[/tex] and [tex]b=-23[/tex].
