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icloudfanboy

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Answer:

0 and 1

Step-by-step explanation:

Given :

[tex]y= 2x-3\\y=2x^{2} -3[/tex]

Now equate the both equation :

[tex]2x-3=2x^{2} -3[/tex]

2x=2[tex]x^{2}[/tex]

x-[tex]x^{2}[/tex]=0

x(1-x)=0

x=0

1-x=0

x=1

Therefore, x=0,1

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