Respuesta :

wegnerkolmp2741o

Answer:

6

Step-by-step explanation:

3log3(9)

Rewriting 9 as 3^2

3log3(3^2)

Using log a^b = b loga

3 * 2log3(3)

We know log 3 (3) =1

3*2 (1)

6
3*log3(3^2) = 3*2*log3(3)= 3*2*1=6

Otras preguntas