p=70°
q=32°
r=38°
Answer:
Solution given:
r=38°[inscribed angle on a same arc are equal]
p=½*140°=70°[inscribed angle is half of the central angle]
<OBA=38°[base angle of isosceles triangle]
again
<C=<B[inscribed angle is half of the central angle]
70°=<OBA+q
70°=38°+q
q=70°-38°
q=32°
