Answer:
209
Step-by-step explanation:
Given the following:
[tex]a_{1} = 17\\d=6[/tex]
The nth term of an arithmetic sequence is expressed as:
[tex]a +(n-1)d[/tex]
a is the first term = 17
d is the common difference =6
Get the 33rd term:
[tex]n=33\\a_{33}=17+(33-1)*6\\a_{33} =17+32(6)\\a_{33}=17+192\\a_{33}=209[/tex]
Hence the 33rd term is 209
