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Answer:
Solution given:
[tex]\bold{4*3^{x+1}-9^{x}=27}[/tex]
let 3^xbe a
4*a*3-a²=27
a²-12a+27=0
a²-9a-3a+27=0
a(a-9)-3(a-9)=0
(a-9)(a-3)=0
either
a=9
3^x=3²
:.x=2
or
a=3
3^x=3^1
x=1
x=2,1