hmartinezmelendez22 hmartinezmelendez22
  • 14-07-2021
  • Mathematics
contestada

у = 3(х – 4)2 – 8
How do you write this in standard form

Respuesta :

theleangreenbean
theleangreenbean theleangreenbean
  • 14-07-2021

Answer:

[tex]y = 3x^2-24x+40[/tex]

Step-by-step explanation:

Hi there!

Standard form: [tex]y=ax^2+bx+c[/tex]

[tex]y = 3(x-4)^2-8[/tex]

Solve [tex](x-4)^2[/tex]

[tex]y = 3(x^2-8x+16)-8[/tex]

Multiply 3 by the parentheses

[tex]y = 3x^2-24x+48-8\\y = 3x^2-24x+40[/tex]

I hope this helps!

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