Given,
initial velocity, u = 10m/s
acceleration, a = -8m/s²
time, t = 2s
[tex]we \: know \: that \\ s = ut + \frac{1}{2}a {t}^{2} \\ = > s = (10m {s}^{ - 1} \times 2s) + ( \frac{1}{2} \times (- 8m {s}^{ - 2}) \times {(2s)}^{2}) \\ = >s = 10m + (- 8m) \\ = > s = 2m[/tex]
This is the answer.
Hope it helps!!
