moon2009 moon2009

11-08-2021
Mathematics

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if y - 1/y =8 then find the value of y^2-1/y^3

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Аноним Аноним

11-08-2021

Step-by-step explanation:

[tex] {y}^{2} - \frac{1}{ {y}^{3} } [/tex]

factorise out y² ;

[tex] = {y}^{2} (1 - \frac{1}{y} ) \\ \\ = 8 {y}^{2} [/tex]

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