hisilatamang2 hisilatamang2

13-08-2021
Mathematics

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The H.C.F. of m²-n² and (m-n)² is ...

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rdilkumari rdilkumari

13-08-2021

Answer:

(m-n)

Step-by-step explanation:

1st expression=

[tex] = {m}^{2} - {n}^{2} \: \: \: \: \: \: \: \: \: \: [/tex]

=(m-n) (m+n)

2nd expression=

[tex] ({m - n})^{2} [/tex]

=(m-n)(m-n)

therefore H.C.F=(m-n)

taking common (m-n)

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