Respuesta :

jisooo42
Third one is your answer

Answer:

[tex]4( \sqrt[5]{ {x}^{2} y} ) + 3( \sqrt[5]{ {x}^{2}y } ) \\ [/tex]

factorise out the 5th root of x²y :

[tex] = \sqrt[5]{ {x}^{2}y } (4 + 3) \\ = 7( \sqrt[5]{ {x}^{2} y} )[/tex]

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