Respuesta :

r3t40

The bit on the i-th position from RIGHT to LEFT has a value of 2 to the i (start counting with 0), so,

First one is,

[tex]0\cdot2^3+1\cdot2^2+0\cdot2^1+1\cdot2^0=5[/tex]

The next are thusly,

[tex]2,0,6[/tex] and 8.

Hope this helps :)

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