Answer: B. 3x (1 - 3x²)
Step-by-step explanation:
Given
[tex]\frac{9x^4-27x^6}{3x^3}[/tex]
Factorize the numerator
=[tex]\frac{3x^3*3x-3x^3*9x^3}{3x^3}[/tex]
=[tex]\frac{9x^4(3x-9x^3)}{3x^3}[/tex]
Cancel terms in numerator and denominator
=[tex]\frac{3x(1-3x^2)}{1}[/tex]
=[tex]\boxed {3x(1-3x^2)}[/tex]
Hope this helps!! :)
Please let me know if you have any questions
