Answer:
Formula used :
- (a^m)^n = a^(m×n)
- a^m × a^n = a^(m+n)
[tex]27 \times {9}^{3x} = {3}^{k} \\ {3}^{3} \times { {(3}^{2}) }^{3x} = {3}^{k} \\ {3}^{k} = {3}^{3} \times {3}^{(2 \times 3x)} \\ {3}^{k} = {3}^{3} \times {3}^{6x} \\ {3}^{k} = {3}^{(6x + 3)} \\ \boxed{k = 6x + 3}[/tex]
- k = (6x+3) is the right answer.
