Answer:
0
Step-by-step explanation:
[tex]\frac{-x-|4y|}{2x+y}[/tex] ( substitute x = - 8, y = 2 into the expression )
= [tex]\frac{-(-8)-|4(2)|}{2(-8)+2}[/tex]
= [tex]\frac{8-|8|}{-16+2}[/tex]
= [tex]\frac{8-8}{-14}[/tex]
= [tex]\frac{0}{-14}[/tex]
= 0
