Answer:
[tex]y = \frac{4}{5} x - \frac{22}{5} [/tex]
Step-by-step explanation:
[tex]y = mx + b[/tex]
[tex] - 2 = \frac{4}{5} (3) + b \\ - 2 = \frac{12}{5} + b \\ - 2 - \frac{12}{5} = b \\ - \frac{10}{5} - \frac{12}{5} = b \\ - \frac{22}{5} = b[/tex]
Therefore, the equation of the line that goes through point (3, -2)and has slope ⅘ is
[tex]y = \frac{4}{5} x - \frac{22}{5} [/tex]
