Respuesta :
The velocity of the watermelon as it hits the ground is 14.715 m/s.
Given the data in the question;
Since the Watermelon was dropped from rest,
- Initial velocity of the Watermelon;[tex]u = 0m/s[/tex]
- Time taken for the Watermelon to hit the ground; [tex]t = 1.5s[/tex]
- We know that, Acceleration due to gravity; [tex]g = 9.81 m/s^2[/tex]
Now, we determine the velocity of the watermelon as it hits the ground which is the final velocity.
From the First Equation of Motion:
[tex]v = u + at[/tex]
Now, under gravity, acceleration ''a" will Acceleration due to gravity;[tex]g = 9.81m/s^2[/tex], "v" is the final velocity, "u" is the initial velocity and "t" is the time taken.
So, we substitute our values into the equation
[tex]v = 0m/s\ +\ ( 9.81m/s^2\ * 1.5s )\\\\v = ( 9.81m/s^2\ * 1.5s )\\\\v = 14.715 m/s[/tex]
Therefore, the velocity of the watermelon as it hits the ground is 14.715 m/s
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