9514 1404 393
Answer:
log(128) = t·log(2)
Step-by-step explanation:
You can take logarithms the way the formula is, or you can simplify it first.
As is
log(10000) = log(625) -log(8) +t·log(2)
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Simplified
8·10000/625 = 2^t . . . . . multiply by 8/625
128 = 2^t
log(128) = t·log(2)
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Solution:
t = log(128)/log(2) = 7
