Answer:
[tex]q\le \:12[/tex]
Step-by-step explanation:
Solving
[tex]\mathrm{Switch\:sides}[/tex] (Not a required step)
[tex]q+3\le \:15[/tex]
[tex]\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}[/tex]
[tex]q+3-3\le \:15-3\\=q\le \:12[/tex]
[tex]\bold{q\le \:12}[/tex]
Graphing
