Answer:
(c) (12th root of 8)^x
Step-by-step explanation:
The applicable rules of exponents are ...
[tex](a^b)^c=a^{bc}\\\\\sqrt[n]{a}=a^{1 \! /n}[/tex]
In this case, we have ...
[tex](\sqrt[3]{8})^{x/4}=8^{1/3\cdot x/4}=8^{x/12}=\boxed{\left(\!\sqrt[12]{8}\right)^x}[/tex]
