ZeZe11
ZeZe11
14-01-2017
Mathematics
contestada
distance between (3,10) and (-4,31)
Respuesta :
texaschic101
texaschic101
14-01-2017
(3,10)(-4,31)
distance = sqrt (x2 - x1)^2 + (y2 - y1)^2
distance = sqrt (-4 - 3)^2 + (31 - 10)^2
distance = sqrt (-7^2 + 21^2)
distance = sqrt (49 + 441)
distance = sqrt 490
distance = 7 sqrt 10 or 22.14
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