Answer:
x = - [tex]\frac{3}{8}[/tex]
Step-by-step explanation:
Given a parabola in standard form
f(x) = ax² + bx + c ( a ≠ 0 )
Then the equation of the axis of symmetry is
x = - [tex]\frac{b}{2a}[/tex]
f(x) = 8x² + 6x + 19 ← is in standard form
with a = 8 and b = 6 , then equation of axis of symmetry is
x = - [tex]\frac{6}{16}[/tex] = - [tex]\frac{3}{8}[/tex]
