Answer:
Other root: [tex]x=3[/tex]
[tex]q=6[/tex]
Step-by-step explanation:
If [tex]x=2[/tex], then [tex]x-2=0[/tex].
Therefore:
[tex]x^2-5x+q=0[/tex]
[tex]2^2-5(2)+q=0[/tex]
[tex]4-10+q=0[/tex]
[tex]-6+q=0[/tex]
[tex]q=6[/tex]
This means that the other root is [tex]x=3[/tex] since [tex](x-2)(x-3)=x^2-5x+6[/tex]
