osbornej93 osbornej93

14-03-2022
Mathematics

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If t(d) = 3d + 1 and d(n) = 4n + 2, what is t(d(n)) in terms of n?

Respuesta :

14-03-2022

Answer:

t(d(n)) = 12n + 7

Step-by-step explanation:

t(d) = 3d + 1
d(n) = 4n + 2

t(d(n)) = t(4n + 2)

Substitute the function d(n) into the function t(d) for the variable d.

t(4n + 2) = 3(4n + 2) + 1

12n + 6 + 1
12n + 7

t(d(n)) = 12n + 7

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