Answer:
[tex]\frac{2y-1}{3y+1}[/tex]
Step-by-step explanation:
[tex]\frac{2-\frac{1}{y} }{3+\frac{1}{y} }[/tex] ( multiply numerator and denominator by y to clear the fractions )
[tex]\frac{2-\frac{1}{y} }{3+\frac{1}{y} }[/tex] × [tex]\frac{y}{y}[/tex]
= [tex]\frac{2y-1}{3y+1}[/tex]
