Respuesta :

loneguy

[tex]\text{pH} = -\log[H^{+}]\\\\\implies \log[H^{+}] = -\text{pH}\\\\\implies [H^{+}] = 10^{-\text{pH}}}\\\\\implies [H^{+}] =10^{-3.75}=0.00017~M[/tex]

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