4025703 4025703
  • 14-04-2022
  • Chemistry
contestada

What is the pressure, in atmospheres, of 14.3 moles of a gas at a temperature of 485 K in a 187 liter container?

P
V
=
n
R
T


R = 0.0821
a
t
m
⋅
L
m
o
l
⋅
K

Respuesta :

jjcrittmd258 jjcrittmd258
  • 15-04-2022

Answer:

3.04 atm

Explanation:

First note r is in l*atm/mole*K

PV=nRT

P = nRT/V = 14.3(.0821)(485)/187 = 3.04 atm

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