Respuesta :

Answer:

43.18 gm

Explanation:

Heat of fusion of water at 0° C is 334  j/gm

 then you have to heat the water to boiling point (100 C)

    specific heat of water is 4.186 j/g-c

x = grams of water

x ( 334 + 4.186 (100) ) = 32500

x = 43.18 gm

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