Answer: x=0 x=2i x=-2i
if your factoring: x(x^2+4)
Step-by-step explanation:
(if your solving for x)
[tex]x^{3} +4x\\x(x^{2} +4)\\\\x=0\\\\x=\frac{-b}{2a}\frac{+}{-} \frac{\sqrt{b^2-4ac}}{2a} \\\\x=\frac{0}{2}\frac{+}{-} \frac{\sqrt{0^2-16}}{2} \\x={0}}\frac{+}{-} \frac{\sqrt{-16}}{2} \\[/tex]
[tex]x={0}}\frac{+}{-} \frac{4i}{2} \\\\\\x=\frac{+}{-}2i[/tex]
