zacqui123 zacqui123

15-07-2022
Mathematics

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Find the solutions of each equation on the interval [0,2pi)

sin(3pi/2+ x)+sin(3pi/2 +x)= -2

Find the solutions of each equation on the interval 02pi sin3pi2 xsin3pi2 x 2 class=

Respuesta :

dhondishaurya dhondishaurya

15-07-2022

Answer:

x=0

Step-by-step explanation:

You can combine the equation to get 2sin(3/2 +x) = -2

divide both sides by 2 and you get the equation equal to -1. sin is equal to -1 when the value inside is 3/2 so this is the answer.

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