Answer:
Hello,
Step-by-step explanation:
[tex]27x^3-\dfrac{9}{2}x^2+\dfrac{1}{4}x-\dfrac{1}{216} \\\\=(3x)^3-3*(3x)^2*\dfrac{1}{6} +3*(3x)*(\dfrac{1}{6} )^2-(\dfrac{1}{6} )^3\\\\=\boxed{(3x-\dfrac{1}{6} )^3}[/tex]
