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  • 14-02-2017
  • Mathematics
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H=K+log(A/C)
isolate a... make a the subject

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arthurpdc
arthurpdc arthurpdc
  • 14-02-2017
[tex]H=K+\log\left(\dfrac{A}{C}\right)\\\\ \log\left(\dfrac{A}{C}\right)=H-K\\\\ \dfrac{A}{C}=10^{H-K}\\\\ \boxed{A=C\cdot10^{H-K}}[/tex]
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