2w²+w=5
⇒2w²+w-5
= 0
here a=2, b=1 and c = -5
[tex]x = \frac{-b \pm \ (b^2-4ac) }{2a} \\ \\ \Rightarrow x = \frac{-1 \pm \ \sqrt{(1)^2-4*2*(-5)} }{2*2} \\ \\ \Rightarrow x = \frac{-1 \pm \ \sqrt{1+40} }{2*2} \\ \\ \Rightarrow x= \frac{-1+ \sqrt{41} }{4} \ and\ \frac{-1- \sqrt{41} }{4} [/tex]
