SOLUTION:
Case: Circle equations
Metho:
[tex](x-a)^2+(y-b)^2=r^2[/tex]
Given:
[tex]\begin{gathered} (x+11)^2+(y-6)^2=9 \\ (x+11)^2+(y-6)^2=3^2 \end{gathered}[/tex][tex]\begin{gathered} Center(a,b)=(-11,6) \\ radius,r=3 \end{gathered}[/tex]
Final answer:
Center (-11, 6)
radius, r= 3
