We have to write the equation of the line that pass through (4,-5) and (2,0).
We can calculate the slope as:
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{0-(-5)}{2-4}=\frac{5}{-2}=-2.5[/tex]
We can then write the slope-point form of the equation as:
[tex]\begin{gathered} y-y_0=m(x-x_0) \\ y-0=-2.5(x-2) \\ y=-2.5x+5 \end{gathered}[/tex]
Answer: y=-2.5x+5
