Answer:
B. 2[(x² + 5)(x + 3)]
Step-by-step explanation:
All coefficients are even, so a factor of 2 can be removed. Then we notice that pairs of terms have the same ratio of coefficients, so we can factor by grouping.
2(x³ +3x² +5x +15) = 2(x²(x +3) +5(x +3)) = 2(x² +5)(x +3)
