JungIdaacochanolem JungIdaacochanolem

11-04-2017
Chemistry

contestada

A reaction has ?h?rxn= -129 kj and ?s?rxn= 301 j/k .

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Аноним Аноним

14-04-2017

I was thinking that the question would be to find for the operating temperature of the reaction. Change in entropy is equal to the total energy divided by the temperature. Assuming it is isothermal, internal energy would be zero. Therefore, the temperature would be:

T = 129000/301 = 428.57 K

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