taylorngibson
taylorngibson
12-05-2017
Mathematics
contestada
how to solve and the answer
Respuesta :
Аноним
Аноним
12-05-2017
the 1 / y^-2 = 1 / 1 / y^2 = y2
so the expression becomes (x^-3 y^2)^-1 the -1 outside the parentheses = 1/ what s inside so we get
1 / (y^2 x^-3) = x^3/y^2 or x^3 y^-2
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Аноним
Аноним
13-05-2017
y^2/x^3 or y^2 over x^3
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