The graph of the parent quadratic function, f(x)=x^2, is shifted right 6 units and down 2 units. What is the function written in standard form for the translated parabola?
(y-k) =a(x-h)² Where k indicates the vertical shift & h, the horizontal one. In your original function f(x) = x², k=h=0. That means the parabola passes by the origine & since a=1>0, it opens up, Now if you want to shifted it 6 units at the right that means h=6 & 2 units at 2 units down that means k= -2 Plug these value into the standard form & you will get: y-(-2)= (x-6)² or ==> y+2 = (x-6)² or y= (x-6)² -2
