chi118r0 chi118r0
  • 12-07-2017
  • Chemistry
contestada

Consider the chemical equation.

2NBr3 + 3NaOH --> N2 + 3NaBr + 3HOBr

If there are 40 mol of NBr3 and 48 mol of NaOH, what is the excess reactant?

N2
NBr3
NaOH
HOBr

Respuesta :

dec77cat dec77cat
  • 12-07-2017
NBr₃ : NaOH = 2 : 3
40    :    48    = 2 : 2.4
40    :    48    = 2.5 : 3

NBr₃ is the excess reactant
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kiban254
kiban254 kiban254
  • 03-10-2018

NBr₃ is the answer young man.

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