viahaley1
viahaley1
13-05-2015
Mathematics
contestada
(1+sinx/cos^2x) = tan^2x + 1 + tanxsecx
Respuesta :
hunaifirst
hunaifirst
13-05-2015
#ANSWER#
(1+sinx/cos²x) =tan²x+1+tanx . secx
-> [(1+sinx/cos²x)] = 1/cos²x+sinx/
-> cos²x
-> = sec²x+tan x sec x
-> =tan²x+1+tanx secx
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