Answer:
(- 16, 0 )
Step-by-step explanation:
Since the centre of the dilatation is at the origin
multiply each of the coordinates of P by the scale factor of 4
P (- 4, 0 ) → P' (- 4(4) , 0(4) ) → P' (- 16, 0 )
The coordinates of the image of vertex P are (- 16, 0 )
