Answer:
C) 210
Step-by-step explanation:
Using binomial expansion for
[tex](x+y)^10[/tex]
we have general term
[tex]T_{r+1} =10Cr x^{10-r} y^r,r=0,1,2,3....10[/tex]
Now we want the term which has 10-r =6 or r =4
Hence coefficient would be
10C4
= [tex]\frac{10(9)(8)(7)}{1(2)(3)(4)} \\=210[/tex]
Hence answer is option C
210
