we will use cos
[tex]cos(\theta)=\frac{adjacent}{hypotonuse}[/tex]
solving for hyptonuse
[tex]hypotonuse=\frac{adjacent}{cos(\theta)}[/tex]
given that the angle (theta) is 24.5 degrees and the adjacent side is 81.8
[tex]hypotonuse=\frac{81.8}{cos(24.5^o)}[/tex]
hyptonuse≈89.8939 m
about 90m is te length of the hypotnuse
