Respuesta :

nikvist

Answer:

Step-by-step explanation:

[tex]y'=8x-2y,\quad y_p=mx+b,\quad y'_p=m\\m=8x-2(mx+b)=(8-2m)x-2b\\(2m-8)x+m+2b=0\\2m-8=0,\quad m+2b=0\\m=4,\quad b=-m/2=-2\\m+b=2[/tex]

Otras preguntas